Question

You sell sandwiches. 70% of people choose chicken, the rest choose something else. Here, p(success) = 0.7 and p(not_success) = 0.3. What is the probability of selling 2 chicken sandwiches to the next 3 customers? N = 3, x= 2, p= 0.7

Answer 1

here's your answer. Hope it will work thanks. Please mark me brainlist.

Answer 2

Answer:

0.441

Step-by-step explanation:

binomial distribution:

nCp * p^x * (1-p)^n-x =

3C2 * (0.7)^2 * (0.3)^3-2 =

0.441