Question

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Answer 1

${2}^{x} = {2}^{2y} = {2}^{3z}$
$x = 2y = 3z$

Now, given that
$\frac{1}{2x} + \frac{1}{4y} + \frac{1}{4z} = 4$

$\frac{1}{2x} + \frac{1}{4 (\frac{x}{2} )} + \frac{1}{4( \frac{x}{3}) } = 4$

$\frac{1}{2x} + \frac{1}{2x} + \frac{3}{4x} = 4$

$\frac{1}{x} + \frac{3}{4x} = 4$

$\frac{7}{4} = 4x$

$x = \frac{7}{16}$