Question

z=-1+3i then theta is equal to​

Answer 1

Answer:

$z = - 1 + 3i \\ \\ arg \: \theta = { \tan}^{ - 1} ( \frac{3}{ - 1} ) \\ = \pi - { \tan }^{ - 1} 3$

z = -1 +3i it is located 2nd quadrant.

so (π - something)