zero of the polynomial p(x) =cx + d, c # 0,c,d are real number
Answers
Answered by
43
let p(x)=0
⇒cx+d=0
⇒cx=0-d
⇒cx=-d
⇒x=-d/c
=p(x)=cx+d
=p(-d/c)=c(-d/c)+d
=-d+d
=0
so the -d/c is a zero of the p(x)
⇒cx+d=0
⇒cx=0-d
⇒cx=-d
⇒x=-d/c
=p(x)=cx+d
=p(-d/c)=c(-d/c)+d
=-d+d
=0
so the -d/c is a zero of the p(x)
Similar questions