Question

zero point 24 gram of sample of compound of Oxygen and Boron was found by analysis to contain 0.096 gram of 4 and 0.144 gram of oxygen calculate the percentage composition of the compound by weight

Answer 1

$\% \: boron \: = \frac{mass \: of \: solute}{mass \: of \: solution } \times 100$

$\%boron = \frac{0.096}{0.24} \times 100 \times \frac{1000}{1000}$

$\%boron = \frac{96}{24} \times 10$

% boron = 40%
% oxygen = (100-40)% = 60%