Question

Zeroes of p(z) = z2

– 27 are ______ and ______.​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Zeroes of p(z) = z² - 27 are - 3√3 and 3√3

Given :

The polynomial p(z) = z² - 27

To find :

Zeroes of p(z) = z² - 27 are ____ and ____

Solution :

Step 1 of 2 :

Write down the given polynomial

The given polynomial is

p(z) = z² - 27

Step 2 of 2 :

Find zeroes of the polynomial

For Zero of the polynomial p(z) we have

p(z) = 0

$\displaystyle \sf{ \implies {z}^{2} - 27 = 0}$

$\displaystyle \sf{ \implies {z}^{2} = 27 }$

$\displaystyle \sf{ \implies z = \pm \: \sqrt{27} }$

$\displaystyle \sf{ \implies z = \pm \: \sqrt{3 \times 3 \times 3} }$

$\displaystyle \sf{ \implies z = \pm \: \sqrt{ {3}^{2} \times 3} }$

$\displaystyle \sf{ \implies z = \pm \: 3 \sqrt{ 3} }$

Hence zeroes of p(z) = z² - 27 are - 3√3 and 3√3

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