Question

0.1 A current flowing through a 100 ohm resistor for 2 minutes. a.claculate the heat relased. b. calculate the power

Answer 1

Answer:

see the attachment

Explanation:

hope the answer will help you

Answer 2

Answer:

a) heat released =120 J

b)power =1 watt

Explanation:

a) I= 0.1A ,. r=100 ohm,. t=2mins=120sec

according to Joule law of heating

w=I^2Rt

=0.1*0.1*100*120

=120J

b) power is the rate at which work is done.

p=w/t

= I^2Rt/t

=120/120=1

therefore,power=1 watt

Hope it helps you!

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