Question

[1÷2(1^3)][-10(1)[1÷5(1^2)] please​

Answer 1

Answer❣

Solution

=>8x²-14x-9=0

The above equation is in the form of a quadratic equation so,we simply factorise it by middle term splitting method.

Step by step explanation:

How to factorise..??

8x²-14x-9=0

The coefficient of x² is 8

-14x is a middle term and its coefficient is 14.

and the constant" is +3

Step-1 : Multiply the coefficient of x² by the constant -9×8= -72

Step-2 : Find two factors of 72 whose sum is equal to the coefficient of the middle term, which is -14.

=>8x²-14x-9=0

-9×8= -72

-72 = -18× 4

and -18+4= -14

=>8x²-14x-9=0

=>8x²-18x+4x-9=0

=>2x(4x-9)+1(4x-9)=0

=>(2x+1)(4x-9)=0

=>2x+1=0

=>2x= -1

=>x= -1/2

(4x-9)=0

=>4x=9

=>x=9/4

∴ x = -1/2 & x = 9/4

✌✌✌✌✌✌✌✌✌✌

hope that u r helpful

please follow thank and brinlylist please

Thank You...♡♡

Answer 2

Answer:

[1÷2(1^3)][-10(1)[1÷5(1^2)] answer is -1