Question

1.A 50Ω transmission line is terminated in a load impedance of (150+j200) Ω. The normalized load impedance is_____.

Answer 1

Given that,

Load impedance = (150+j200) Ω

Input impedance load = 50 Ω

We need to calculate the normalized load impedance

Using formula of output load impedance

$Z_{o}^2=Z_{in}\times Z_{L}$

Where, $Z_{in}$ = input impedance load

$Z_{L}$ = Load impedance

Put the value into the formula

$Z_{o}^2=50\times(150+j200)$

$Z_{o}=\sqrt{7500+j10000}\ \Omega$

$Z_{o}=(86.6+j100)\ \Omega$

Hence, The normalized load impedance is $(86.6+j100)\ \Omega$