Question

1. (a) निम्नलिखित समीकरण को तुलनात्मक विधि से
हल कीजिए :
15x +3y = 39
12x +9y= 51​

Answer 1

Answer:

$15x +3y = 39 \: \: \: \: \: \: \: ...(1) \\ </p><p>12x +9y= 51 \: \: \: \: \: \: \: \: ...(2)\\ \\ from \: equation \: (1) \\ y = \frac{39 - 15x}{3} \\ \\ substituting \: the \: value \: of \: y \: in \: equation \: (2) \\ 12x + 9(\frac{39 - 15x}{3}) = 51 \\ 12x + 117 - 45x = 51 \\ 45x - 12x = 117 - 51 \\ 33x = 66 \\ x = \frac{66}{33} \\ x = 2 \\ \\ from \: equation \: (1) \\ y = \frac{39 - 15x}{3} \\ = \frac{39 - 15 \times 2}{3} \\ = \frac{39 - 30}{3} = \frac{9}{3} = 3$