Question

1
An open tank is filled which Hg upto a height of 76cm. What is the pressure at the
bottom of the tank?
(A) 3 atm
(B) 2 atm
(C) 4 atm
(D) 1 atm
(ii)
middle of the tank. (If atmospheric pressure is 1 atm) ?
76 cm
(A) 2 atm
(B) 1.0 atm
(C) 2.5 atm
(D) 1.5 atn​

Answer 1

Answer:tyuio

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Answer 2

Given:

Height of tank(h)=76cm=76/100=0.76m

Atmospheric Pressure (ρatm.)=1 atm

Pressure at the bottom of the tank(ρ)=?

Acceleration due to gravity(g)=9.8m/s²

Density of mercury(d)=13546 kg/m³

∴ Pressure of Hg(ρHg) = $d.h.g$ =13546×0.76×9.8= 100890.608 P = 1 atm

To find the pressure (ρ) at the bottom of the tank

Solution:

ρ=ρatm+ ρHg

ρ=1+1

ρ=2 atm

Again,

To find the pressure (ρ') at the middle of the tank where ρHg =1atm/2

ρ'=ρatm+ρHg

ρ'=1+1/2

ρ'=1+0.5

ρ'=1.5 atm

Hence, the pressure of at the bottom of the tank and at the middle is 2 atm and 1.5 atm respectively if the standard atmospheric pressure is 1 atm.

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