If a,b,c are in A.P, then show that a(b+c)/bc,b(c+a)/ca and c(a+b)/ab are also in A.p
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step by step:
abc are in AP
a(b+c)/bc , b(c+a)/ca , c(a+b)/ab
on adding 1 to it , we get
a(b+c)/bc + 1 , b(c+a)/ca + 1 , c(a+b)/ab + 1 = (ab + bc + ac)/bc , (ab + bc + ac)/ac , (ab + bc + ac)/ab
On dividing by (ab + bc + ac) , we get
= 1/bc , 1/ac , 1/ab
On multiplying by abc , we get
= a ,b ,c
So, a(b+c)/bc , b(c+a)/ca , c(a+b)/ab are in A.P
hope this helps
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