Question

1) find the zeros of the folowing quadratics polynomial and verify the relationship between the zeros and the co-officients
i. ×^2-2×-8​

Answer 1

Answer

roots = 4 and -2

Step-by-step explanation:

Here,

x^2-2x-8=0

By Splitting the middle term

x^2-4x+2x-8=0

(x^2-4x)+(2x-8)=0

(x-4)(x+2)=0

Hence, x= 4,-2

Now a = 1  b = -2  c = -8

alpha+beta= -b/a

4+(-2) = -(-2)/1

4-2=2/1

2=2

alpha x beta = c/a

4 x (-2) = (-8)/1

-8 = -8

Hence Proved.