Physics, asked by ruparna75, 5 months ago

1 mole of gas is initially at 0°C . It is allowed to expand at constant pressure to double it's volume. How much heat is required? given Cv=20.7J mol^-1K^-1 and R= 8.31 J mol^-1 K^-1.​

Answers

Answered by prantik2009
0

Answer:

(a) Specific Heat Capacity at Constant Volume (cv) ... Total energy, U = mN 3 [(1/2) KT], Here m is the number of moles of the gas and N ... C v =1/m (dU/dT) = (1/m) (m3N) (1/2 k) = (3/2) R.

Answered by honeyhd10
0

Answer:

In isothermal reversible expansion,

we have;

w=−2.303∗nRTlog  V2/V1

w=2.303∗1∗8.314∗298log 20 /10

​w=2.303∗1∗8.314∗298log2

w=−1779.6J

w=2.303∗1∗2∗298log2=−206.6cal.

Similar questions