Question

1 mole of PCI (g) with 2 moles of Cl2(g) were
placed in 3 lit vessel and heated to 400 K.
When equilibrium was established only 0.7
moles of PCI3, remained. What is the value
of equilibrium constant Kc for the reaction
PCI3 +Cl2. =PCI5​

Answer 1

Answer:

1.79

Explanation:

kc =product / reactant

kc=[0.7]/[0.3][1.3]

kc=0.7÷0.39

kc=1.79

Make as brillant

Answer 2

Answer:

I am sorry I can't answer.....