Question

1 P×P =Q 6.Q-P= 3.Find the value of Q &P.

Answer 1

p
${p}^{2} = 6q \\ q = \frac{ {p}^{2} }{6} \\ { \frac{ {p}^{2} }{6} } - p = 3 \\ \frac{ {p}^{2} - 6p}{6} = 3 \\ {p }^{2} - 6p = 18 \\ {p}^{2} - 6p - 18 = 0$
solve it