Question

(1+ tan sqQ)(1-sinsqQ)

Answer 1

( 1 + tan ^2 Q ) ( 1 - sin^2 Q )
The steps are as follows :
sec^2 × cos ^2 = 1 ^2= 1

Answer 2

${ \sec }^{2} q \times { \cos }^{2}q$
$\frac{1}{ { \cos }^{2}q } \times { \cos}^{2}$
= 1

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