1 the perimeter of rectangle is 17 cm. if its width is this is mixed fraction 3 3 by 4 centimetre find its length
2 solve a. x-2=17
b. x/3+1=7/15
c. x-3/7=-14/3
d. x/3+3/2=5/2
e. t+3/4=27/4
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Perimeter of rectangle = 2 (l + b)
It is given that
b = 3 3/4
= 15/4 Cm
And Perimeter = 17 Cm
Thus
17 = 2 (l + 15/4)
l + 15/4 = 17/2
l = 17/2 - 15/4
l = 21/4 Cm
It is given that
b = 3 3/4
= 15/4 Cm
And Perimeter = 17 Cm
Thus
17 = 2 (l + 15/4)
l + 15/4 = 17/2
l = 17/2 - 15/4
l = 21/4 Cm
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