Question

1 upon 3x+y +1 upon 3x- y = 3/4

Answer 1

Answer:

$\frac{1}{3x+y} + \frac{1}{3x-y} = \frac{3}{4}$

$\implies \frac{3x-y+3x+y}{(3x+y)(3x-y)} = \frac{3}{4}$

$\implies \frac{6x}{(3x)^{2} - y^{2}} = \frac{3}{4}$

$\implies 6x \times \frac{4}{3} = (3x)^{2} - y^{2}$

$\implies 2x \times 4 = 9x^{2} - y^{2}$

$\implies 8x = 9x^{2} - y^{2}$

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