(11) Electric current through resistance 4 in the given circuit is (a)0.5A (b) 12/7A (c) 2/7A (d) zero
Answers
Answer:
Correct option is
C
2/7A
The circuit can be reduced, step by step, to a single equivalent resistance. The 8 ohm and the 8 ohm are connected in parallel , and so they can be replaced by an equivalent resistor Rp of 4 ohms, using the below equation.
Rp=
(8+8)
(8×8)
=4 ohms
This resistor is connected in series with the 4 ohm resistor R1. The total resistance Rt of the circuit is then
R
t
=R
1
+R
p
=4+4=8 ohms.
Since the 4 ohm and the 4 ohm are connected in series, they have the same current I1, which must be equal to the current of the battery. Using Ohms law we get,
I=
R
V
=
8
8
=1A.
Hence, the current flowing through the resistor R1 (4 ohms) is 1A.
Explanation:
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Answer:
Pattern: Basic problems based on peak, RMS and mean value of current and the voltage.
Description: The RMS value of the current is considered to be a constant value of current that flows in a circuit whereas the peak value is the maximum current obtained from the sinusoidal alternating current.