Question

a³a²b + ab² - b³ factorise the following polynomials by grouping the terms​

Answer 1

Answer:

a³ + b³ = (a + b)(a² – ab + b²)

WHY?

BECAUSE:—

(a + b)³ = a³ + 3ab(a + b) + b³

then a³ + b³ = (a + b)³ – 3ab(a + b)

= (a + b)[(a + b)² – 3ab]

= (a + b)(a² + 2ab + b² – 3ab)

= (a + b)(a² – ab + b² )

 

Answer 2

Answer:

a³ + b³ = (a + b)(a² – ab + b²)

WHY?

BECAUSE:—

(a + b)³ = a³ + 3ab(a + b) + b³

then a³ + b³ = (a + b)³ – 3ab(a + b)

= (a + b)[(a + b)² – 3ab]

= (a + b)(a² + 2ab + b² – 3ab)

= (a + b)(a² – ab + b² )

 

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