Question

(1²+2²+3²+.....20²=2870. then (2²+4²+6²+.....+40²=?

Answer 1

Answer is 11480

Step-by-step explanation:

Mutiply the first equation by 4

Answer 2

The required value is 9880.

Step-by-step explanation:

Since we have given that

$1^2+2^2+3^2+...................+20^2=2870$

We need to find the value of

$2^2+4^2+6^2+............+40^2$

Since,

$2^2(1^2+2^2+3^2+..........+20^2\\\\=2^2\times 2470\\\\=4\times 2470\\\\=9880$

Hence, the required value is 9880.

# learn more:

Resistances of 40 ohm and 60 ohm are connected in series across a 200 V battery. find the heat in calories produced by the combination in 1/2 minute.

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