Question

12. ABCD is a parallelogram. CE is drawn parallel to DB meeting AB produced at E. Prove tha
BE = DC (or equivalently, B is the mid-point of AE).

​

Answer 1

Answer:

plzz mark as brainlist

Step-by-step explanation:

Given that BE II AC

ABEC is a parallelogram, of which opposite sides are parallel.

Δ ABC and Δ ACE lie on the same base AC and between the same parallel AC and BE.

Area(Δ ABC) = Area(Δ ACE)

By adding area(Δ ADC) to both sides

Area(Δ ABC) + Area(Δ ADC) = Area(Δ ACE) + Area(Δ ADC)

Area (Parallelogram ABCD) = Area(Δ ADE)

Hence, proved.

Answer 2

Step-by-step explanation:

i have answers but give me sometime . I'm answers in a shortly way of manner !! by the way I'm sorry for mine inconvenience !!#