15. A body is dropped from a height of 320m. The acceleration due to gravity is 10m/s2.. a) How long it will take to reach the ground. b) What is the velocity with which it strikes the ground?
Answers
Answered by
21
HEY BUDDY..!!!
HERE'S THE ANSWER...
________________________
a = 10 m / s^2 ; s = 320 m ; u = 0
Firstly
=> v^2 = u^2 + 2 a s
=> v^2 = 2 × 10 × 320
=> v^ = 6400
=> v = 80 m / s ( it strikes the ground )
( a ) t = ?
Now ,
=> v = u + a t
=> t = v / a
=> t = 80 / 10
=> t = 8 s
HOPE HELPED..
HAVE A NICE DAY..
:-)
HERE'S THE ANSWER...
________________________
a = 10 m / s^2 ; s = 320 m ; u = 0
Firstly
=> v^2 = u^2 + 2 a s
=> v^2 = 2 × 10 × 320
=> v^ = 6400
=> v = 80 m / s ( it strikes the ground )
( a ) t = ?
Now ,
=> v = u + a t
=> t = v / a
=> t = 80 / 10
=> t = 8 s
HOPE HELPED..
HAVE A NICE DAY..
:-)
Similar questions