Question

2. A point object is 24 cm above the surface of water. u=4/3 in a lake. A fish inside the water
will observe the object to be at a point
(A)
B 2 cm above the surface.
18 cm above the surface,
6cm below the surface.
(D) W
6 cm above the surface.​

Answer 1

Answer:

A fish inside the water observes the object to be at a height of 18 cm above the surface of the water.

(B) is correct option.

Explanation:

Given that,

Refractive index $\mu=\dfrac{4}{3}$

Distance of object = 24 cm

We need to calculate the apparent distance

Using formula of apparent distance

$\mu=\dfrac{D}{d}$

Where, d = apparent distance

D = real distance

Put the value into the formula

$\dfrac{4}{3}=\dfrac{24}{d}$

$d=\dfrac{3}{4}\times24$

$d=18\ cm$

Hence, A fish inside the water observes the object to be at a height of 18 cm above the surface of the water.