2 cubes each of volume 64cm are joined end to end .find the surface area of the resulting cuboid
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Answered by
3
We know that volume of the cube = a^3.
Given, a^3 = 64cm
a^3 = 4^3
a = 4cm.
Length will be 4+4 = 8cm and breadth = 4cm and height = 4cm.
Surface area of the resulting cuboid = 2(lb+bh+hl)
= 2(32+16+32)
= 2(80)
= 160 cm^2.
Given, a^3 = 64cm
a^3 = 4^3
a = 4cm.
Length will be 4+4 = 8cm and breadth = 4cm and height = 4cm.
Surface area of the resulting cuboid = 2(lb+bh+hl)
= 2(32+16+32)
= 2(80)
= 160 cm^2.
Answered by
1
Answer: 160cm².
Step by step explanation:
Given,
Volume of both cubes = 64cm³
Volume of one cube =a³
⇒ 64 = a³
⇒ (4) = a³
⇒ a=4
We know that, when two cubes are joined they form cuboid:
Length of cuboid=4+4= 8cm
Breadth of cuboid= 4cm
Height of cuboid= 4cm
Surface area of cuboid = 2(lb+bh+lh)
2(8×4+4×4+4×8)
= 2(32+16+32)
= 2(80)
= 160cm²
Therefore, Surface area of Cuboid is 160 cm².
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