Question

2) In the figure, O is the centre of the circle.
mZAOB = 75°, then find
(i) m(arc AXB)
(ii) m(arc AYB).​

Answer 1

Answer:

m(arcAXB) =75

m(arcAXB+m(arc AYB)=360

75 +. arc AYB =360

arc AYB =285