2
show that (sin theta + cos theta)^2
+ (sino - cos)² = 2
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2
Answer:
____________________?
Answered by
0
Answer:
(sinѲ + cosѲ )² + (sinѲ - cosѲ )²
= 2( sin²Ѳ + cos²Ѳ )
= 2 ×1
=2
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