Math, asked by rojahm8, 1 year ago

√2.sin(45°+A)=sinA+cosA

Answers

Answered by nishthatagra1

16

√2(Sin 45+A)=√2(Sin45CosA+Cos45SinA)

√2(Sin 45+A)=√2(1/√2cosA+1/√2SinA)

√2(Sin 45+A)=CosA+SinA

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