2 year ago, father was three times as old as his son and two two years hens twice his age will be equal to five times that of his son . find the present age...
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Answers
Son’s age = X
Two years ago son’s age = X – 2
His Father’s age at that time = 3(X – 2)
Present age of Father = 3X – 6 + 2
The present age of Father = 3X – 4
Two years hence father’s age = 3X – 4 + 2
Two years hence father’s age = 3X – 2
Two years hence son’s age = X + 2
Given:
5 × (X + 2) = 2 × (3X – 2)
5X + 10 = 6X – 4
X = 14
Son’s present age X = 14 years.
Father’s present age = (3 × 14) – 4
Father’s present age = 38 years.
Answer:
Two years ago, father was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Find their presents ages. Son's present age X = 14 years. Father's present age = 38 years.
Step-by-step explanation:
Let us consider
Son’s age = X
Two years ago son’s age = X – 2
His Father’s age at that time = 3(X – 2)
Present age of Father = 3X – 6 + 2
The present age of Father = 3X – 4
Two years hence father’s age = 3X – 4 + 2
Two years hence father’s age = 3X – 2
Two years hence son’s age = X + 2
Given:
5 × (X + 2) = 2 × (3X – 2)
5X + 10 = 6X – 4
X = 14
Son’s present age X = 14 years.
Father’s present age = (3 × 14) – 4
Father’s present age = 38 years.