Question

25) Person is observed, the top of the tower of height 10m from distance of 1043 m from foot
of the tower, find the angle of elevation.​

Answer 1

Answer:

Given the tower is 30m away from point A.

Given angle of elevation of top of tower is 30.

Let the height of tower be x

tan30=

AB

BC

=

3

1

=

30

x

x=

3

30

⋅

3

3

=

3

30×

3

=10

3

∴ Height of tower =10

3

=10×1.732

=17.32m.