Question

(2a-b
$(2a - b) {}^{2} + 2(2a - b) - 8$
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Answer 1

Simplify:

Step-by-step explanation:

$\ Given \ value:\\\\(2a-b)^2+2(2a-b)-8\\\\\ Solution:\\\\(2a-b)^2+2(2a-b)-8 = 0\\\\(a-b)^2 = a^2 +b^2 -2ab\\\\\rightarrow (2a)^2+(b)^2-2(2a)(b)+4a-2b-8 = 0\\\\\rightarrow 4a^2+b^2-4ab+4a-2b-8 = 0\\\\\rightarrow 4a^2+4a+b^2-2b-4ab-8 = 0\\\\\rightarrow 4a(a+1)+b(b-2)-4(ab+2) = 0$

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