Question

Question No : 1
What is the ratio of surface energy of 1 small drop and 1 large drop, if 1000 small drops combined to form 1 large
drop
1) 100:1
2) 1000:1
3) 10:1
4) 1:100

Answer 1

Answer:

Surface energy of water drop= 2S/R

( S= surface tension, R= radius of drop)

Now , vol. of 1000 small drops= vol. of 1 big drop

1000×4/3 π r^3 = 4/3 π R^3

(r= rad. of small drop, R= rad. of big drop)

Hence, R= 10r

Now, Surface tension of 1 small drop= 2S/r

Surface tension of 1 big drop = 2S/R

ratio- 2S/r : 2S/R

1/r : 1/R

R:r

10r:r (R=10r)

10:1

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Answer 2

Step-by-step explanation:

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