Question

2H2S+3O2 GIVES 2H2O+2SO2 Predict the sign of delta S

Answer 1

n= no of moles of gasious product. - no of moles of gasious reactants
n = (2+2)-(3+2)= - 1
since n is negative so randomness decreases
and sign of Delta S is -ve

Answer 2

Answer: The sign of $\Delta S$ will be negative.

Explanation:

The value of $\Delta S$ depends on the change of number of moles.

If the change in number of moles is positive, the value of $\Delta S$ is positive and if the change in number of moles is negative, the value of $\Delta S$ is negative.

For the given chemical reaction:

$2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)$

The value of change in number of moles is:

$\Delta n_g=(2+2)-(2+3)=-1$

As, the change in number of moles of gases is coming out to be -1, the $\Delta S$ will be negative.

Hence, the sign of $\Delta S$ will be negative.