Question

(3/5^-4)×(5/3^3k+1)=(3/5)-40 please do

Answer 1

here u can write your equation as (5/3)^4*(5/3)^(3k+1) = (5/3)^40
                                   here, (5/3)^(4+3k+1)= (5/3)^40
 since bases are same powers are equal
                              therefore, 4+3k+1=40   
                            therefore, 3k=40-5=35 ,   k =35/3 ans