3(a+c).(b+c) = what
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3(ab+ac+bc+c^2) =3ab+3ac+3bc+3a^2
Anonymous:
Yes correct Answer
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3(a+c).(b+c)
=(3a+3c)(b+c)
=3a(b+c)+3c(b+c)
=3ab+ 3ac+3bc+3c square
=3(ab+ac+bc+c2)
I HOPE IT WILL HELP YOU
=(3a+3c)(b+c)
=3a(b+c)+3c(b+c)
=3ab+ 3ac+3bc+3c square
=3(ab+ac+bc+c2)
I HOPE IT WILL HELP YOU
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