3 odd consecutive numbers whose sum is 741
Answers
Answered by
0
Let the numbers be x, x+2 and x+4
Then
x+x+2+x+4=741
3x+6=741
3(x+2)=741
x+2=741/3
x+2=247
x=247-2
x=245
Then numbers are 245,245+2=247 and 245+4=249
Verification
245+247+249
492+249
=741
Hence my answer is correct
Then
x+x+2+x+4=741
3x+6=741
3(x+2)=741
x+2=741/3
x+2=247
x=247-2
x=245
Then numbers are 245,245+2=247 and 245+4=249
Verification
245+247+249
492+249
=741
Hence my answer is correct
Answered by
0
Let the second number be x
Then the previous number will be x-2
And the next number will be x+2
Now (x-2)+x+(x+2) =741
3x=741
X=247
The previous number is 245 and the next is 249
The numbers are 245,247 and 249.
Hope it helps......!
Then the previous number will be x-2
And the next number will be x+2
Now (x-2)+x+(x+2) =741
3x=741
X=247
The previous number is 245 and the next is 249
The numbers are 245,247 and 249.
Hope it helps......!
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