Question

3) The maximum kinetic energy of photo electron emitted from a surface when
photons of energy 6 eV falls on it is 4 eV. The stopping potential is_ V
(A) 6 (8) 2 (C) 10 (D) 4
​

Answer 1

Answer:

2 eV

Explanation:

E = E0 + KE

E = energy of photon

E0 = Work function

KE = kinetic energy of electron

KE = E - E0 = 6 - 4 = 2 eV

Pls, mark me if you understand...