Question

3 ^(x+2) = 243 , then find te value of 3^x+726

Answer 1

3^under root n + 726

3^n+2 = 3^5

n+2 = 5

n = 5-2

n= 3

and 3under root n + 726 =

3 under root 3 + 726

= 3 under root 729

= 3*27

= 81

Answer 2

#ur Ans
__________

Given that

$= > \: {3}^{(x + 2)} = 243 \\ \\ now \: we \: can \: change \: into \\ same \: denominator \\ \\ factor \: of \: 243 \\ \\ = > 243 = 3 \times 3 \times 3 \times 3 \times 3 \\ \\ now \\ \\ = > {3}^{(x + 2)} = {3}^{5} \\ \\ = > here \: base \: is \: same \: then \\ we \: can \: solve \: the \: power \: \\ value \\ \\ = > x + 2 = 5 \\ = > x = 5 - 2 \\ = > x = 3 \\ \\ = > now \: put \: the \: value \: of \: x \\ \\ = > {3}^{x} + 726 \\ \\ = > {3}^{3} + 726 \\ \\ = > 27 + 726 \\ \\ = > 753 \: ans$


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