Math, asked by shubhvora40, 1 year ago

30 points please solve and send

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Answered by Anonymous
2
Let a – d , a, a + d are the first three terms.

Sum of three terms = 18

 a – d + a + a + d = 18

                     3a = 18

                       a = 18/3

                       a = 6

Sum of their squares = 140

(a – d)² + a² + (a + d)² = 140

 a² + d² – 2ad + a² + a² + d² + 2ad  = 140

3 a² + 2 d² = 140

3(6)² + 2 d² = 140

 3(36) + 2d² = 140

 108 + 2d² = 140

           2d² = 140 – 108

           2d²= 32

             d²= 32/2

            d²= 16

               d = √16

               d = ± 4

d = 4       d = -4

a = 6    d = 4                        a = 6    d = -4

     2,6,10                                10,6,2

Therefore the three terms are 2,6,10 or 10,6,2


shubhvora40: thank u
shubhvora40: i have another question pl answer
Answered by Anonymous
4
Hey mate ^_^

Check this attachment

#Be Brainly❤️
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shubhvora40: thank u verry much
shubhvora40: are u free can u answer some more questions please i have exam tomorrow
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