Question

30th term of the A.P. : 10, 7, 4, ... is

Answer 1

Answer:

-77

hope it might helps u!!!!

Answer 2

Given :-

• First term (a) = 10

• common difference (d) = 7 - 10 = -3

• n = 30

To find :-

• 30th term of the AP = ?

Solution :-

we know that,

$\orange{\bigstar}\:\:{\underline{\boxed{\bf\red{a_n=a+(n-1)d}}}}$

$\rm\longrightarrow\:a_{30}=10+(30-1)(-3)$

$\rm\longrightarrow\:a_{30}=10+29\times{(-3)}$

$\rm\longrightarrow\:a_{30}=10+(-87)$

$\rm\longrightarrow\:a_{30}=10-87$

$\rm\longrightarrow\:a_{30}=-77$

Hence,the 30th term of AP will be -77,

More Information :-

Formula :-

$\rm\:s_n=\dfrac{n}{2}\:[2a+(n-1)d]$

$\rm\:a_n=a+(n-1)d$

➝ Progression :- Sequences which follow a definite pattern are called progression.

➝ Arithmetic progression :- A sequence in which each term differs from its preceding term by a constant is called an arithmetic progression.It is denoted by AP.