√32-√128+√200 solve please
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√32=4√2
√128=8√2
√200=10√2
then
substitute the given values
we get
4√2-8√2+10√2
take √2 as common
√2[4-8+10]
√2[6]
=>6√2
√128=8√2
√200=10√2
then
substitute the given values
we get
4√2-8√2+10√2
take √2 as common
√2[4-8+10]
√2[6]
=>6√2
BHAND:
thanks bruh
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