Math, asked by BHAND, 1 year ago

√32-√128+√200 solve please

Answers

Answered by vyaswanth

3

√32=4√2
√128=8√2
√200=10√2

then

substitute the given values

we get

4√2-8√2+10√2

take √2 as common

√2[4-8+10]

√2[6]

=>6√2

BHAND: thanks bruh

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