32,64,96,128,Find the HCF of the given number by prime factorisation and continued division method.
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Answered by
72
Prime factorisation method :
1 ) 32 = 2^5
2 ) 64 = 2^6
3 ) 96 = 2^5 × 3
4 ) 128 = 2^7
Therefore,
HCF ( 32 , 64 , 96 , 128 ) = 2^5
= 32
I hope this helps you.
: )
1 ) 32 = 2^5
2 ) 64 = 2^6
3 ) 96 = 2^5 × 3
4 ) 128 = 2^7
Therefore,
HCF ( 32 , 64 , 96 , 128 ) = 2^5
= 32
I hope this helps you.
: )
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Answered by
33
By Prime factorisation method:
The prime factors of 32 = 2 x 2 x 2 x 2 x 2
The prime factors of 64 = 2 x 2 x 2 x 2 x 2 x 2
The prime factors of 96 = 2 x 2 x 2 x 2 x 2 x 3
The prime factors of 128 = 2 x 2 x 2 x 2 x 2 x 2 x 2
The common factors are 2 x 2 x 2 x 2 x 2 = 32.
Therefore the HCF is 32.
By Division method:
32)64(2 Therefore HCF od 32 and 64 is 32.
64
-------------
X
32)96(3 Therefore HCF od 32 and 96 is 32.
96
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X
32)128(4 Therefore HCF od 32 and 128 is 32.
128
-------------
X
Thus HCF is 32.
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