Question

4(p+q)(3a-b)+6(p+q)(2b_3a)

Answer 1

Here's you answer

4(p+q)(3a-b)+6(p+q)(2b-3a) = 2(p+q)[2(3a-b) + 3(2b-3a)] = 2(p+q)[6a - 2b + 6b - 9a] = 2(p+q)[4b - 3a]

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