Question

I will mark the first answer brainliest so please answer it fast

Answer 1

since ABCD is a square, show AB = BC = CD = AD
also he is an equilateral triangle, so AD = DE = AE
NOW WE CAN SAY
AB = BC = CD = AD = DE = AE
Now in triangle ABE,
we get AB = AE
which means ABE is an isosceles triangle.
and Angle BAE=angle BAE + angle DAE
→Angle BAE = 90° + 60° = 150°
SINCE ABE is an isosceles triangle,
we can say angle ABE = angle AEB.
SO in Triangle BAE,
angle ABE + angle AEB + angle BAE = 180°
2 × (angle ABE) = 180° - 150° = 30°
angle ABE = angle AEB = 15°.
now find your answer, it's easy now.

Answer 2

$if \: all \: sides \: are \: equal \: and \: all \: angles \: are 60 \: then \: it \: is \: an \: equilateral \: triangle$

ABCD is a square, so all angles are 90. A=B=C=D=90.___1). EAD=60. So, In ∆AEB. EAB=EAF+FAB=60+90= 150______2). In ∆AEB, A+E+B=180. 150+x+x=180; we get, x=15. In ∆AED, E=60. AED=AEF+FED ; 60= 15+FED. so, FED=45. In ∆FED, D=60. F+E+D=180. so, F+60+45= 180. we get, F= 75. F=y =75