Question

44
Question 19
-1
A stone thrown from the top of a building is
given an initial velocity of 20.0 m/s straight
upward. Determine the time in seconds at
which the stone returns to the height from
which it was thrown.
g = 9.8 m/sec2
A: 3.45
B: 3.46
C: 4.52.
D: 4.08​

Answer 1

Answer:

i give clue to solve it ok - u-20 & v-0 because when it reached to it stop for few micro second and g-9.8 ,use formula H-ut+1/2 gt square use g equal -9.8 because it goes upward