4x+5y=40,x-axix and y-axix x=5,y=4 find area of triangle
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This is simple logic my friend
Let's do it!
first of all given is 4x+5y=40
where x=5 & y=4.
here in the given equation, 4x is x-axis and 5y is y-axis.
Now,Let's substitute x and y in the given equation
4 (5)+5 (4) =40
20 + 20 = 40
therefore, x-axis=20 & y-axis= 20.
now let's take x-axis as Base of the triangle and y-axis as height of the triangle.
As ar (triangle) = 1/2 x b×h.
= 1/2 × 20×20
= 1/2 × 40
= 40/2 = 20 cm or m Sq.
Hope this helps you my friend
Plz mark this as brainlieast answer.
thanks
Let's do it!
first of all given is 4x+5y=40
where x=5 & y=4.
here in the given equation, 4x is x-axis and 5y is y-axis.
Now,Let's substitute x and y in the given equation
4 (5)+5 (4) =40
20 + 20 = 40
therefore, x-axis=20 & y-axis= 20.
now let's take x-axis as Base of the triangle and y-axis as height of the triangle.
As ar (triangle) = 1/2 x b×h.
= 1/2 × 20×20
= 1/2 × 40
= 40/2 = 20 cm or m Sq.
Hope this helps you my friend
Plz mark this as brainlieast answer.
thanks
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