5.6 liters if gas at STP are found to have a mass of 11g. The molecular mass of gas is
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v=5.6
m=11g
at STP
p=1 atm
t=273 k and by ideal gas equation
PV=nRt. n=m÷M
PV=mRT÷M
1×5.6=(11×0.082×273)÷M
M=43.33 approx..
molecular Mass M =43.33
m=11g
at STP
p=1 atm
t=273 k and by ideal gas equation
PV=nRt. n=m÷M
PV=mRT÷M
1×5.6=(11×0.082×273)÷M
M=43.33 approx..
molecular Mass M =43.33
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