Chemistry, asked by yadavmamta9932, 5 months ago

50 ml of 0.1 M solution of KHC,0,. H.CO, is titrated with different reagents separately.

The titre value obtained will be

Answers

Answered by nainikakumarigupta70
0

Answer:

Assume that a mixture of Na

2

C

2

O

4

and KHC

2

O

4

.H

2

C

2

O

4

required 1 L of 0.2 M KMnO

4

and 1 L of 0.2 M NaOH separately for complete titration.

1 L of 0.2 M NaOH corresponds to 1L×0.2mol/L=0.2 moles of NaOH.

1 mole of KHC

2

O

4

.H

2

C

2

O

4

will react with 3 moles of NaOH.

So 0.2 moles of NaOH will react with

3

0.2

=0.0667 moles of KHC

2

O

4

.H

2

C

2

O

4

.

1 L of 0.2 M KMnO

4

corresponds to 1L×0.2mol/L=0.2 moles of KMnO

4

5 moles of Na

2

C

2

O

4

will react with 2 moles of KMnO

4

.

0.2 moles of KMnO

4

will react with

2

5

×0.2=0.5 moles of Na

2

C

2

O

4

The mole ratio Na

2

C

2

O

4

: KHC

2

O

4

H

˙

2

C

2

O

4

= 0.5:0.0667=

2

15

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