Question

50 ml of 0.5 M oxalic acid is needed to neutralise 12.5 ml of Ca(OH)2 solution. The amount of Ca(OH)2 in 100 ml of given Ca(OH)2 solution is 7.4 g 74 g 5.6 g 4 g​

Answer 1

Answer:

H

2

C

2

O

4

+2NaOH→Na

2

C

2

O

4

+2H

2

O

m

eq

of H

2

C

2

O

4

=m

eq

of NaOH

50×0.5×2=25×N

NaOH

×1

∴M

NaOH

=N

NaOH

=2 M ; since n-factor is 1

Now, 1000 ml solution =2×40 gram NaOH

∴50 ml solution =4 gram NaOH.

Answer 2

Answer:

the answer is 74 g hope this answer will help you